NBA legendary star, how many years has Kobe been the first player in the league in his 20 years?

What kind of performance can be considered the number one player in the league? Whether looking at a single season, a stage or the entire NBA history, the most important thing is dominance. Dominance is composed of multiple factors, the most important thing is personal performance and team performance. If both are good, then they must be the number one person in the league.

If you want to look at the first player in the league in a single season, aside from the controversy of voting, then the MVP+FMVP in a single season is basically the first player in the league. In the future, a round of +FMVP is also very convincing.

The star to be evaluated today is Kobe. He has played in the NBA for a total of 20 seasons. Which seasons are he considered the No. 1 player in the league?

First of all, Kobe is a defender, and two stars will enter the first team in a season. Therefore, if Kobe can't even enter the first team, he will definitely not be the first in the league. After all, he will not be in the top 2 of the defenders in the regular season. Unless he performs against the playoffs, it will be difficult to win back the first team in the season.

Kobe entered the first team of the All-Season 11 times, namely: 01-02, 02-03, 03-04, 05-06, and 12-13 season. So, in these 11 years, what years can Kobe be called the No. 1 player in the league?

With poor performance in the playoffs:

02-03 season, Kobe was in the first team, but was eliminated in the second round of the playoffs. Both MVPs are Duncan, and the number one player in the league in the season is Duncan, and there is no controversy.

05-06 season, Kobe was in the first round of the playoffs, but was eliminated. The regular season MVP is Nash and the FMVP is Wade. In the 2006-07 season, Kobe was in the first round of the playoffs, but was eliminated. The regular season MVP is Nowitzki and the FMVP is Parker. The situation in these two seasons is similar. Kobe performed very well personally, but the team's performance is not good, so he is definitely not the first person.

Bryant in the 10-11 season, but was eliminated in the second round of the playoffs. In the 11-12 season, Kobe was in the first team, but was eliminated in the second round of the playoffs. In the 12-13 season, Kobe was in the first round, but the season was reimbursed and he did not play in the playoffs, so the Lakers were eliminated in the first round.

These three seasons are similar. With Kobe's performance in the playoffs, it is indeed difficult to be the number one player in the league. Even if no one in the league is better than Kobe, with such a result, I believe Kobe himself will not regard himself as the number one player.

is obviously the first player in the league in the season:

08-09 season, Kobe was in the first team, led the team to win the championship in the playoffs and was elected as FMVP. The regular season MVP of the season was James, and James' team was eliminated in the Eastern Conference Finals. It is obvious that Kobe must be the first player in the 2008-09 season.

The 09-10 season is basically the same as the 08-09 season. The difference is that Kobe achieved two consecutive championships, and the team where MVP James is eliminated in the second round, so the number one player in the league this season must be Kobe.

3 seasons remaining:

07-08 season, Kobe is the MVP, the team reached the finals in the playoffs, lost to the Celtics, and Pierce won the FMVP. Kobe is the runner-up of MVP+ this season, and among other stars, the only ones who may compete with Kobe are left:

Pierce: FMVP+Champion+Three Teams, Garnett: Best Defensive Player+Champion+1 Teams.

If FMVP is Garnett, then Garnett will undoubtedly be better, but in reality, Kobe can be regarded as the number one player in the league in the 2007-08 season. In the

01-02 season, Kobe was in the first team and the team also won the championship, but the FMVP was O'Neal's. O'Neal is also the first team of the best team in the regular season, and in terms of MVP voting, O'Neal is third and Kobe is fifth. It can only be said that Kobe is very good, but the number one player in the season should be O'Neal. In the 02-03-04 season, Kobe was in the first match and the team eventually lost to the Pistons in the finals.

Kobe is the first team + runner-up, Billups is the FMVP + champion + failed to enter the best team, Ben Wallace is the second team + champion, Garnett is the MVP + eliminated in the Western Conference Finals, and O'Neal is the first team + runner-up.

The civilian team Pistons won the championship this year, resulting in no particularly top players in the season, but it is indeed difficult for Kobe to claim himself as the first person.

In summary, from the 2007-08 season to 2009-10 season, Kobe was the well-deserved number one in the league, and in addition, Kobe can only be regarded as the top 5 in the league. This top 5 may be between 2nd and 5th.